Thickness of a circuit board
Topic: Functions of random variables and limit theorems · more questions on this topic
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Boards should have thickness between 0.146 cm and 0.154 cm. A machine produces thickness X\sim\operatorname{N}(0.151, 0.003^2).
Find the probability that one board meets the specification. Use \Phi(1)\approx 0.8413 and \Phi(1.67)\approx 0.9525.
Let \overline X be the mean thickness of 25 independent boards from this machine. Find the probability that the batch mean meets the same specification.
Worked answer (click to show)
- Standardise the limits 0.146 and 0.154 with mean 0.151 and standard deviation 0.003:
\mathbb{P}(0.146\le X\le 0.154)=\Phi(1)-\bigl(1-\Phi(1.667)\bigr)\approx 0.8413-(1-0.9525)=0.794.
- The batch mean is \operatorname{N}(0.151, 0.003^2/25). The standardised limits are -8.33 and 5. Both are so far into the tails that the probability is 1 for any ordinary purpose.