Five draws without replacement
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Five numbers are drawn without replacement from \{1,\ldots,100\}. Find the probability that exactly three of them are even.
Worked answer (click to show)
The draw is hypergeometric: 5 items from 100, of which 50 are even.
\mathbb{P}(X=3)=\frac{\binom{50}{3}\binom{50}{2}}{\binom{100}{5}}\approx 0.319.