The smaller face
Two fair dice are thrown and Z is the smaller of the two faces.
Give the probability mass function of Z in a table.
Calculate \mathbb{E} Z.
Worked answer (click to show)
- There are 36 equally likely ordered pairs. The number of pairs whose minimum is z is 11,9,7,5,3,1 for z=1,\ldots,6: the pairs in which both faces are at least z, minus the pairs in which both are at least z+1.
| z | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| \mathbb{P}(Z=z) | 11/36 | 9/36 | 7/36 | 5/36 | 3/36 | 1/36 |
- \mathbb{E} Z=(1\cdot 11+2\cdot 9+3\cdot 7+4\cdot 5+5\cdot 3+6\cdot 1)/36=91/36.