Bivariate exponential example

Section of Markov chains, Gibbs sampling, and Metropolis–Hastings, part of Bayesian statistics

Bivariate exponential example

Type Section
Taught in Markov chains, Gibbs sampling, and Metropolis–Hastings
Part Bayesian statistics

Example 1 (Bivariate exponential target) The target is

\pi(x_1,x_2)\propto e^{-x_1x_2-x_1-x_2}, \qquad x_1,x_2\geq0.

Question. Derive both full conditional distributions and use them to specify a systematic-scan Gibbs sampler.

Solution. To obtain X_1\mid X_2=x_2, hold x_2 fixed: \begin{align*} \pi(x_1\mid x_2) &\propto\pi(x_1,x_2)\\ &\propto e^{-x_1x_2-x_1-x_2}\\ &\propto e^{-x_1(x_2+1)}, \qquad x_1\geq0. \end{align*} The omitted factor e^{-x_2} is constant in x_1. Normalising gives

\pi(x_1\mid x_2)=(x_2+1)e^{-(x_2+1)x_1},

so

X_1\mid X_2=x_2\sim\operatorname{Exp}(x_2+1).

By symmetry,

X_2\mid X_1=x_1\sim\operatorname{Exp}(x_1+1).

Starting from any nonnegative pair (x_1^{(0)},x_2^{(0)}), the sampler is \begin{align*} x_1^{(t+1)}&\sim\operatorname{Exp}(x_2^{(t)}+1),\\ x_2^{(t+1)}&\sim\operatorname{Exp}(x_1^{(t+1)}+1). \end{align*}

Used in

See also

Markov chain · Stationarity and detailed balance · Detailed balance implies stationarity · Systematic-scan Gibbs sampler · Warm-up is not a convergence proof · Metropolis–Hastings update · Metropolis–Hastings invariance · Markov chains and equilibrium

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